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(x-8)10x=7x+39
We move all terms to the left:
(x-8)10x-(7x+39)=0
We multiply parentheses
10x^2-80x-(7x+39)=0
We get rid of parentheses
10x^2-80x-7x-39=0
We add all the numbers together, and all the variables
10x^2-87x-39=0
a = 10; b = -87; c = -39;
Δ = b2-4ac
Δ = -872-4·10·(-39)
Δ = 9129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-87)-\sqrt{9129}}{2*10}=\frac{87-\sqrt{9129}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-87)+\sqrt{9129}}{2*10}=\frac{87+\sqrt{9129}}{20} $
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