(x-y)dx+(x-y+1)dy=0

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Solution for (x-y)dx+(x-y+1)dy=0 equation:


Simplifying
(x + -1y) * dx + (x + -1y + 1) * dy = 0

Reorder the terms for easier multiplication:
dx(x + -1y) + (x + -1y + 1) * dy = 0
(x * dx + -1y * dx) + (x + -1y + 1) * dy = 0

Reorder the terms:
(-1dxy + dx2) + (x + -1y + 1) * dy = 0
(-1dxy + dx2) + (x + -1y + 1) * dy = 0

Reorder the terms:
-1dxy + dx2 + (1 + x + -1y) * dy = 0

Reorder the terms for easier multiplication:
-1dxy + dx2 + dy(1 + x + -1y) = 0
-1dxy + dx2 + (1 * dy + x * dy + -1y * dy) = 0

Reorder the terms:
-1dxy + dx2 + (dxy + 1dy + -1dy2) = 0
-1dxy + dx2 + (dxy + 1dy + -1dy2) = 0

Reorder the terms:
-1dxy + dxy + dx2 + 1dy + -1dy2 = 0

Combine like terms: -1dxy + dxy = 0
0 + dx2 + 1dy + -1dy2 = 0
dx2 + 1dy + -1dy2 = 0

Solving
dx2 + 1dy + -1dy2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), 'd'.
d(x2 + y + -1y2) = 0

Subproblem 1

Set the factor 'd' equal to zero and attempt to solve: Simplifying d = 0 Solving d = 0 Move all terms containing d to the left, all other terms to the right. Simplifying d = 0

Subproblem 2

Set the factor '(x2 + y + -1y2)' equal to zero and attempt to solve: Simplifying x2 + y + -1y2 = 0 Solving x2 + y + -1y2 = 0 Move all terms containing d to the left, all other terms to the right. Add '-1x2' to each side of the equation. x2 + y + -1x2 + -1y2 = 0 + -1x2 Reorder the terms: x2 + -1x2 + y + -1y2 = 0 + -1x2 Combine like terms: x2 + -1x2 = 0 0 + y + -1y2 = 0 + -1x2 y + -1y2 = 0 + -1x2 Remove the zero: y + -1y2 = -1x2 Add '-1y' to each side of the equation. y + -1y + -1y2 = -1x2 + -1y Combine like terms: y + -1y = 0 0 + -1y2 = -1x2 + -1y -1y2 = -1x2 + -1y Add 'y2' to each side of the equation. -1y2 + y2 = -1x2 + -1y + y2 Combine like terms: -1y2 + y2 = 0 0 = -1x2 + -1y + y2 Simplifying 0 = -1x2 + -1y + y2 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

d = {0}

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