(x/(x+1))-(3(x+2))=1

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Solution for (x/(x+1))-(3(x+2))=1 equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

x/(x+1)-(3*(x+2)) = 1 // - 1

x/(x+1)-(3*(x+2))-1 = 0

x/(x+1)-3*(x+2)-1 = 0

x/(x+1)+(-3*(x+2)*(x+1))/(x+1)+(-1*(x+1))/(x+1) = 0

x-3*(x+2)*(x+1)-1*(x+1) = 0

-3*x^2-8*x-x-6-1 = 0

-3*x^2-9*x-7 = 0

-3*x^2-9*x-7 = 0

-1*(3*x^2+9*x+7) = 0

3*x^2+9*x+7 = 0

DELTA = 9^2-(3*4*7)

DELTA = -3

DELTA < 0

-1 = 0

-1/(x+1) = 0

-1/(x+1) = 0 // * x+1

-1 = 0

x belongs to the empty set

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