(x/(x+2))+(4/(x+1))=1

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Solution for (x/(x+2))+(4/(x+1))=1 equation: 


D( x )

x+2 = 0

x+1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-2) U (-2:-1) U (-1:+oo)

x/(x+2)+4/(x+1) = 1 // - 1

x/(x+2)+4/(x+1)-1 = 0

(x*(x+1))/((x+2)*(x+1))+(4*(x+2))/((x+2)*(x+1))+(-1*(x+2)*(x+1))/((x+2)*(x+1)) = 0

x*(x+1)+4*(x+2)-1*(x+2)*(x+1) = 0

x^2-x^2+5*x-3*x-2+8 = 0

2*x+6 = 0

(2*x+6)/((x+2)*(x+1)) = 0

(2*x+6)/((x+2)*(x+1)) = 0 // * (x+2)*(x+1)

2*x+6 = 0

2*x+6 = 0 // - 6

2*x = -6 // : 2

x = -6/2

x = -3

x = -3

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