(x/2)(4+8)=5((x/4)+3)

Solution for (x/2)(4+8)=5((x/4)+3) equation:

(x/2)(4+8)=5((x/4)+3)

We move all terms to the left:

(x/2)(4+8)-(5((x/4)+3))=0

We add all the numbers together, and all the variables

(+x/2)12-(5((+x/4)+3))=0

We multiply parentheses

12x-(5((+x/4)+3))=0

We multiply all the terms by the denominator


12x*4)+3))-(5((+x=0

We add all the numbers together, and all the variables

x+12x*4)+3))-(5((=0

Wy multiply elements

48x^2+x=0

a = 48; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·48·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*48}=\frac{-2}{96}
=-1/48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*48}=\frac{0}{96}
=0
$