(x/2)+(1/3)=(1/6)

Solution for (x/2)+(1/3)=(1/6) equation:

(x/2)+(1/3)=(1/6)

We move all terms to the left:

(x/2)+(1/3)-((1/6))=0

We add all the numbers together, and all the variables

(+x/2)+(+1/3)-((+1/6))=0

We get rid of parentheses

x/2+1/3-((+1/6))=0

We calculate fractions


108x^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

108x^2/()+2=0

We multiply all the terms by the denominator


108x^2+2*()=0

We add all the numbers together, and all the variables

108x^2=0

a = 108; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·108·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{216}=0$