(x/2)+(x-2/4)=(x+4)/2

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Solution for (x/2)+(x-2/4)=(x+4)/2 equation: 



(x/2)+(x-2/4)=(x+4)/2

We move all terms to the left:

(x/2)+(x-2/4)-((x+4)/2)=0

We add all the numbers together, and all the variables

(+x/2)+(+x-2/4)-((x+4)/2)=0

We get rid of parentheses

x/2+x-((x+4)/2)-2/4=0

We calculate fractions


x+4x/()+(-((x+4)*4)/()+()/()=0



We calculate terms in parentheses: +(-((x+4)*4)/()+()/(), so:

-((x+4)*4)/()+()/(

We add all the numbers together, and all the variables

-((x+4)*4)/()+1

We multiply all the terms by the denominator


-((x+4)*4)+1*()



We calculate terms in parentheses: -((x+4)*4), so:

(x+4)*4

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

-(4x+16)

We get rid of parentheses

-4x-16

Back to the equation:

+(-4x-16)



We get rid of parentheses

x+4x/()-4x-16=0

We multiply all the terms by the denominator


x*()+4x-4x*()-16*()=0

We add all the numbers together, and all the variables

4x+x*()-4x*()=0

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