(x/2)+(x/5)=(7/2)

Solution for (x/2)+(x/5)=(7/2) equation:

(x/2)+(x/5)=(7/2)

We move all terms to the left:

(x/2)+(x/5)-((7/2))=0

We add all the numbers together, and all the variables

(+x/2)+(+x/5)-((+7/2))=0

We get rid of parentheses

x/2+x/5-((+7/2))=0

We calculate fractions


8x^2/()+5x/()+()/()=0

We add all the numbers together, and all the variables

8x^2/()+5x/()+1=0

We multiply all the terms by the denominator


8x^2+5x+1*()=0

We add all the numbers together, and all the variables

8x^2+5x=0

a = 8; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·8·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*8}=\frac{-10}{16}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*8}=\frac{0}{16}
=0
$