(x/2)+(x/6)+(x/6)+(x/12)+2=x

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Solution for (x/2)+(x/6)+(x/6)+(x/12)+2=x equation: 



(x/2)+(x/6)+(x/6)+(x/12)+2=x

We move all terms to the left:

(x/2)+(x/6)+(x/6)+(x/12)+2-(x)=0

We add all the numbers together, and all the variables

(+x/2)+(+x/6)+(+x/6)+(+x/12)-x+2=0

We add all the numbers together, and all the variables

-1x+(+x/2)+(+x/6)+(+x/6)+(+x/12)+2=0

We get rid of parentheses

-1x+x/2+x/6+x/6+x/12+2=0

We calculate fractions

There is no solution for this equation

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