(x/2)+2(x-1)=(5x/2)+4

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Solution for (x/2)+2(x-1)=(5x/2)+4 equation: 


x in (-oo:+oo)

2*(x-1)+x/2 = (5*x)/2+4 // - (5*x)/2+4

2*(x-1)+x/2-((5*x)/2)-4 = 0

2*(x-1)+x/2+(-5/2)*x-4 = 0

2*(x-1)+x/2+(-5*x)/2-4 = 0

(2^2*(x-1))/2+x/2+(-5*x)/2+(-4*2)/2 = 0

2^2*(x-1)+x-5*x-4*2 = 0

5*x-5*x-8-4 = 0

-8-4 = 0

-12 = 0

-12/2 = 0

-12/2 = 0 // * 2

-12 = 0

x belongs to the empty set

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