(x/2)+5=1/3(x+14

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Solution for (x/2)+5=1/3(x+14 equation: 



(x/2)+5=1/3(x+14

We move all terms to the left:

(x/2)+5-(1/3(x+14)=0



Domain of the equation: 3(x+14)+5!=0

We move all terms containing x to the left, all other terms to the right

3(x+14)!=-5

x∈R



We add all the numbers together, and all the variables

(+x/2)-(1/3(x+14)+5=0

We get rid of parentheses

x/2-(1/3(x+14)+5=0

We calculate fractions


(3x^2(x+5)/(6x(x+5)+()/(6x(x+5)=0



We calculate terms in parentheses: +(3x^2(x+5)/(6x(x+5)+()/(6x(x+5), so:

3x^2(x+5)/(6x(x+5)+()/(6x(x+5

We can not solve this equation

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