(x/2)+9x/3)=5

Solution for (x/2)+9x/3)=5 equation:

(x/2)+9x/3)=5

We move all terms to the left:

(x/2)+9x/3)-(5)=0

We add all the numbers together, and all the variables

(+x/2)+9x/3)-5=0

We get rid of parentheses

x/2+9x/3)-5=0

We calculate fractions


3x^2/()+18x/()=0

We multiply all the terms by the denominator


3x^2+18x=0

a = 3; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·3·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*3}=\frac{-36}{6}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*3}=\frac{0}{6}
=0
$