(x/2)=(3/x)-12

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Solution for (x/2)=(3/x)-12 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/2 = 3/x-12 // - 3/x-12

x/2-(3/x)+12 = 0

x/2-3*x^-1+12 = 0

1/2*x^1-3*x^-1+12*x^0 = 0

(1/2*x^2+12*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2+12*x^1-3*x^0) = 0

x^1

(1/2)*x^2+12*x-3 = 0

(1/2)*x^2+12*x-3 = 0

DELTA = 12^2-(-3*4*(1/2))

DELTA = 150

DELTA > 0

x = (150^(1/2)-12)/(2*(1/2)) or x = (-150^(1/2)-12)/(2*(1/2))

x = 5*6^(1/2)-12 or x = -5*6^(1/2)-12

x in { -5*6^(1/2)-12, 5*6^(1/2)-12} 

x in { -5*6^(1/2)-12, 5*6^(1/2)-12 }

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