(x/2-x)+(2/3)=(2/x-2)

Solution for (x/2-x)+(2/3)=(2/x-2) equation:

(x/2-x)+(2/3)=(2/x-2)

We move all terms to the left:

(x/2-x)+(2/3)-((2/x-2))=0


Domain of the equation: 2-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-2

x!=-2/1

x!=-2

x∈R



Domain of the equation: x-2))!=0

x∈R


We add all the numbers together, and all the variables

(-1x+x/2)-((2/x-2))+(+2/3)=0

We get rid of parentheses

-1x+x/2-((2/x-2))+2/3=0

We calculate fractions


x^2/2x+4x^2/2x-1x+()/2x=0

We multiply all the terms by the denominator


x^2+4x^2-1x*2x+()=0

We add all the numbers together, and all the variables

5x^2-1x*2x=0

Wy multiply elements

5x^2-2x^2=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$