(x/2x+1)-(3x+2/4x+3)

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Solution for (x/2x+1)-(3x+2/4x+3) equation: 


x in (-oo:+oo)

(x/2)*x-(3*x)-((2/4)*x)-3+1 = 0

(x/2)*x-3*x+(-1/2)*x-3+1 = 0

1/2*x^2-7/2*x-2 = 0

DELTA = (-7/2)^2-(-2*1/2*4)

DELTA = 65/4

DELTA > 0

x = ((65/4)^(1/2)+7/2)/(1/2*2) or x = (7/2-(65/4)^(1/2))/(1/2*2)

x = (65/4)^(1/2)+7/2 or x = 7/2-(65/4)^(1/2)

x in { 7/2-(65/4)^(1/2), (65/4)^(1/2)+7/2 }

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