If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x/3)+(2x)=(1/2)
We move all terms to the left:
(x/3)+(2x)-((1/2))=0
We add all the numbers together, and all the variables
(+x/3)+2x-((+1/2))=0
We add all the numbers together, and all the variables
2x+(+x/3)-((+1/2))=0
We get rid of parentheses
2x+x/3-((+1/2))=0
We calculate fractions
2x^2/()+2x+()/()=0
We add all the numbers together, and all the variables
2x^2/()+2x+1=0
We multiply all the terms by the denominator
2x^2+2x*()+1*()=0
We add all the numbers together, and all the variables
2x^2+2x*()=0
| 4(x-2)=6(x+5)-4x+19 | | x/3+(2x)=1/2 | | x/3=1/5-(5*x) | | 2x-4-3x=-12-3x | | 2x+x=-3x | | x/3=1/5-5x | | .5x+.25x=9 | | (x/3)+(5x)=1/5 | | 0=-4.9t^2+24.6t+50.5 | | 5x-1-2x=3x-1 | | x/3+(5x)=1/5 | | -2x+4x=-4x+18x | | 1/9x+3=150 | | .5+x=3.25 | | (X/4)+2x=1/3 | | 2x+3=16-3(x+5) | | 5x-3x+4=6 | | x4+2x=13 | | 9(8d-5)+13=12$-2 | | (2/3)*(x-5)=(3/4)*(4x-3) | | -t/3=-3π | | (2/3)*(x−5)=(3/4)*(4x−3) | | 3x+4x+6=18 | | 2=-6-8x | | 3x+4x+6=9•2 | | 2/3*(x−5)=3/4*(4x−3) | | 3(x-2)+9=3 | | 53x-2x=8-7x | | R(x)=-x2+24x | | 2/3(x−5)=3/4(4x−3) | | 7x=(5x-5)+(5x-5) | | 23(x−5)=34(4x−3) |