(x/3)+(x/6)=(7/2)

Solution for (x/3)+(x/6)=(7/2) equation:

(x/3)+(x/6)=(7/2)

We move all terms to the left:

(x/3)+(x/6)-((7/2))=0

We add all the numbers together, and all the variables

(+x/3)+(+x/6)-((+7/2))=0

We get rid of parentheses

x/3+x/6-((+7/2))=0

We calculate fractions


24x^2/()+12x^2/()+()/()=0

We add all the numbers together, and all the variables

24x^2/()+12x^2/()+1=0

We multiply all the terms by the denominator


24x^2+12x^2+1*()=0

We add all the numbers together, and all the variables

36x^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{72}=0$