(x/3)-(3x/4)=(1/12)

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Solution for (x/3)-(3x/4)=(1/12) equation: 



(x/3)-(3x/4)=(1/12)

We move all terms to the left:

(x/3)-(3x/4)-((1/12))=0

We add all the numbers together, and all the variables

(+x/3)-(+3x/4)-((+1/12))=0

We get rid of parentheses

x/3-3x/4-((+1/12))=0

We calculate fractions


(-108x^2)/()+48x^2/()+()/()=0

We add all the numbers together, and all the variables

(-108x^2)/()+48x^2/()+1=0

We multiply all the terms by the denominator


(-108x^2)+48x^2+1*()=0

We add all the numbers together, and all the variables

48x^2+(-108x^2)=0

We get rid of parentheses

48x^2-108x^2=0

We add all the numbers together, and all the variables

-60x^2=0

a = -60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-60)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-120}=0$

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