(x/3)-(x/4)=(5/3)

Solution for (x/3)-(x/4)=(5/3) equation:

(x/3)-(x/4)=(5/3)

We move all terms to the left:

(x/3)-(x/4)-((5/3))=0

We add all the numbers together, and all the variables

(+x/3)-(+x/4)-((+5/3))=0

We get rid of parentheses

x/3-x/4-((+5/3))=0

We calculate fractions


(-27x^2)/()+4x/()+()/()=0

We add all the numbers together, and all the variables

(-27x^2)/()+4x/()+1=0

We multiply all the terms by the denominator


(-27x^2)+4x+1*()=0

We add all the numbers together, and all the variables

(-27x^2)+4x=0

We get rid of parentheses

-27x^2+4x=0

a = -27; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-27)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-27}=\frac{-8}{-54}
=4/27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-27}=\frac{0}{-54}
=0
$