(x/3)-2)+6=7x-3

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Solution for (x/3)-2)+6=7x-3 equation: 



(x/3)-2)+6=7x-3

We move all terms to the left:

(x/3)-2)+6-(7x-3)=0

We add all the numbers together, and all the variables

(+x/3)-2)+6-(7x-3)=0

We add all the numbers together, and all the variables

(+x/3)-2)+6-(7x=0

We get rid of parentheses

x/3-2)+6-(7x=0

We multiply all the terms by the denominator


x-7x*3+6-2=0

We add all the numbers together, and all the variables

x-7x*3+4=0

Wy multiply elements

x-21x+4=0

We add all the numbers together, and all the variables

-20x+4=0

We move all terms containing x to the left, all other terms to the right

-20x=-4

x=-4/-20

x=1/5

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