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x in (-oo:+oo)
(x/3+y/5)*(x/3-(y/5)) = 0
(1/3*x+1/5*y)*(1/3*x-1/5*y) = 0
( 1/3*x+1/5*y )
1/3*x+1/5*y = 0 // - 1/5*y
1/3*x = -(1/5*y) // : 1/3
x = (-(1/5*y))/1/3
x = -3/5*y
( 1/3*x-1/5*y )
1/3*x-1/5*y = 0 // + -1/5*y
1/3*x = -(-1/5*y) // : 1/3
x = (-(-1/5*y))/1/3
x = 3/5*y
x in { -3/5*y, 3/5*y }
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