(x/4)+(x/3)=(7/12)

Solution for (x/4)+(x/3)=(7/12) equation:

(x/4)+(x/3)=(7/12)

We move all terms to the left:

(x/4)+(x/3)-((7/12))=0

We add all the numbers together, and all the variables

(+x/4)+(+x/3)-((+7/12))=0

We get rid of parentheses

x/4+x/3-((+7/12))=0

We calculate fractions


36x^2/()+48x^2/()+()/()=0

We add all the numbers together, and all the variables

36x^2/()+48x^2/()+1=0

We multiply all the terms by the denominator


36x^2+48x^2+1*()=0

We add all the numbers together, and all the variables

84x^2=0

a = 84; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·84·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{168}=0$