(x/4)+(x/3)=(7/12)

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Solution for (x/4)+(x/3)=(7/12) equation:



(x/4)+(x/3)=(7/12)
We move all terms to the left:
(x/4)+(x/3)-((7/12))=0
We add all the numbers together, and all the variables
(+x/4)+(+x/3)-((+7/12))=0
We get rid of parentheses
x/4+x/3-((+7/12))=0
We calculate fractions
36x^2/()+48x^2/()+()/()=0
We add all the numbers together, and all the variables
36x^2/()+48x^2/()+1=0
We multiply all the terms by the denominator
36x^2+48x^2+1*()=0
We add all the numbers together, and all the variables
84x^2=0
a = 84; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·84·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{168}=0$

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