(x/4)+(x/3)=(7/2)

Solution for (x/4)+(x/3)=(7/2) equation:

(x/4)+(x/3)=(7/2)

We move all terms to the left:

(x/4)+(x/3)-((7/2))=0

We add all the numbers together, and all the variables

(+x/4)+(+x/3)-((+7/2))=0

We get rid of parentheses

x/4+x/3-((+7/2))=0

We calculate fractions


12x^2/()+16x^2/()+()/()=0

We add all the numbers together, and all the variables

12x^2/()+16x^2/()+1=0

We multiply all the terms by the denominator


12x^2+16x^2+1*()=0

We add all the numbers together, and all the variables

28x^2=0

a = 28; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·28·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{56}=0$