(x/4)+11=(1/20)

Solution for (x/4)+11=(1/20) equation:

(x/4)+11=(1/20)

We move all terms to the left:

(x/4)+11-((1/20))=0

We add all the numbers together, and all the variables

(+x/4)+11-((+1/20))=0

We get rid of parentheses

x/4+11-((+1/20))=0

We calculate fractions


20x^2/()+11+()/()=0

We add all the numbers together, and all the variables

20x^2/()+12=0

We multiply all the terms by the denominator


20x^2+12*()=0

We add all the numbers together, and all the variables

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$