(x/4)+22=3x-4

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Solution for (x/4)+22=3x-4 equation:



(x/4)+22=3x-4
We move all terms to the left:
(x/4)+22-(3x-4)=0
We add all the numbers together, and all the variables
(+x/4)-(3x-4)+22=0
We get rid of parentheses
x/4-3x+4+22=0
We multiply all the terms by the denominator
x-3x*4+4*4+22*4=0
We add all the numbers together, and all the variables
x-3x*4+104=0
Wy multiply elements
x-12x+104=0
We add all the numbers together, and all the variables
-11x+104=0
We move all terms containing x to the left, all other terms to the right
-11x=-104
x=-104/-11
x=9+5/11

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