(x/4)-(x/6)=(2/3)

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Solution for (x/4)-(x/6)=(2/3) equation:



(x/4)-(x/6)=(2/3)
We move all terms to the left:
(x/4)-(x/6)-((2/3))=0
We add all the numbers together, and all the variables
(+x/4)-(+x/6)-((+2/3))=0
We get rid of parentheses
x/4-x/6-((+2/3))=0
We calculate fractions
(-36x^2)/()+54x^2/()+()/()=0
We add all the numbers together, and all the variables
(-36x^2)/()+54x^2/()+1=0
We multiply all the terms by the denominator
(-36x^2)+54x^2+1*()=0
We add all the numbers together, and all the variables
54x^2+(-36x^2)=0
We get rid of parentheses
54x^2-36x^2=0
We add all the numbers together, and all the variables
18x^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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