(x/4)-(x/6)=(2/3)

Solution for (x/4)-(x/6)=(2/3) equation:

(x/4)-(x/6)=(2/3)

We move all terms to the left:

(x/4)-(x/6)-((2/3))=0

We add all the numbers together, and all the variables

(+x/4)-(+x/6)-((+2/3))=0

We get rid of parentheses

x/4-x/6-((+2/3))=0

We calculate fractions


(-36x^2)/()+54x^2/()+()/()=0

We add all the numbers together, and all the variables

(-36x^2)/()+54x^2/()+1=0

We multiply all the terms by the denominator


(-36x^2)+54x^2+1*()=0

We add all the numbers together, and all the variables

54x^2+(-36x^2)=0

We get rid of parentheses

54x^2-36x^2=0

We add all the numbers together, and all the variables

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$