(x/5)+(x/3)=(3/10)

Solution for (x/5)+(x/3)=(3/10) equation:

(x/5)+(x/3)=(3/10)

We move all terms to the left:

(x/5)+(x/3)-((3/10))=0

We add all the numbers together, and all the variables

(+x/5)+(+x/3)-((+3/10))=0

We get rid of parentheses

x/5+x/3-((+3/10))=0

We calculate fractions


30x^2/()+50x^2/()+()/()=0

We add all the numbers together, and all the variables

30x^2/()+50x^2/()+1=0

We multiply all the terms by the denominator


30x^2+50x^2+1*()=0

We add all the numbers together, and all the variables

80x^2=0

a = 80; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·80·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{160}=0$