(x/5)+11=(1/10)

Solution for (x/5)+11=(1/10) equation:

(x/5)+11=(1/10)

We move all terms to the left:

(x/5)+11-((1/10))=0

We add all the numbers together, and all the variables

(+x/5)+11-((+1/10))=0

We get rid of parentheses

x/5+11-((+1/10))=0

We calculate fractions


10x^2/()+11+()/()=0

We add all the numbers together, and all the variables

10x^2/()+12=0

We multiply all the terms by the denominator


10x^2+12*()=0

We add all the numbers together, and all the variables

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$