(x/5)+11=(1/10)

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Solution for (x/5)+11=(1/10) equation:



(x/5)+11=(1/10)
We move all terms to the left:
(x/5)+11-((1/10))=0
We add all the numbers together, and all the variables
(+x/5)+11-((+1/10))=0
We get rid of parentheses
x/5+11-((+1/10))=0
We calculate fractions
10x^2/()+11+()/()=0
We add all the numbers together, and all the variables
10x^2/()+12=0
We multiply all the terms by the denominator
10x^2+12*()=0
We add all the numbers together, and all the variables
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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