(x/5)-(1/x)=(3x+4/15)

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Solution for (x/5)-(1/x)=(3x+4/15) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/5-(1/x) = 3*x+4/15 // - 3*x+4/15

x/5-(3*x)-(1/x)-(4/15) = 0

x/5-3*x-x^-1-4/15 = 0

-14/5*x^1-1*x^-1-4/15*x^0 = 0

(-14/5*x^2-4/15*x^1-1*x^0)/(x^1) = 0 // * x^2

x^1*(-14/5*x^2-4/15*x^1-1*x^0) = 0

x^1

(-14/5)*x^2+(-4/15)*x-1 = 0

(-14/5)*x^2+(-4/15)*x-1 = 0

DELTA = (-4/15)^2-(-1*4*(-14/5))

DELTA = -2504/225

DELTA < 0

x in { } 

x belongs to the empty set

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