(x/5)-(2/5)-(x/3)=(x+1)/2

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Solution for (x/5)-(2/5)-(x/3)=(x+1)/2 equation: 


x in (-oo:+oo)

x/5-(x/3)-(2/5) = (x+1)/2 // - (x+1)/2

x/5-((x+1)/2)-(x/3)-(2/5) = 0

x/5-((x+1)/2)-(x/3)-2/5 = 0

(-1*(x+1))/2+x/5-x/3-2/5 = 0

(-1*3*5*(x+1))/(2*3*5)+(2*3*x)/(2*3*5)+(2*5*(-x))/(2*3*5)+(-2*2*3)/(2*3*5) = 0

2*3*x-1*3*5*(x+1)+2*5*(-x)-2*2*3 = 0

-9*x-10*x-15-12 = 0

-19*x-15-12 = 0

-19*x-27 = 0

(-19*x-27)/(2*3*5) = 0

(-19*x-27)/(2*3*5) = 0 // * 2*3*5

-19*x-27 = 0

-19*x-27 = 0 // + 27

-19*x = 27 // : -19

x = 27/(-19)

x = -27/19

x = -27/19

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