(x/5)-(6x/3)=(7/15)

Solution for (x/5)-(6x/3)=(7/15) equation:

(x/5)-(6x/3)=(7/15)

We move all terms to the left:

(x/5)-(6x/3)-((7/15))=0

We add all the numbers together, and all the variables

(+x/5)-(+6x/3)-((+7/15))=0

We get rid of parentheses

x/5-6x/3-((+7/15))=0

We calculate fractions


(-450x^2)/()+45x^2/()+()/()=0

We add all the numbers together, and all the variables

(-450x^2)/()+45x^2/()+1=0

We multiply all the terms by the denominator


(-450x^2)+45x^2+1*()=0

We add all the numbers together, and all the variables

45x^2+(-450x^2)=0

We get rid of parentheses

45x^2-450x^2=0

We add all the numbers together, and all the variables

-405x^2=0

a = -405; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-405)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-810}=0$