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(x/5)-2(2x/5+1)=28
We move all terms to the left:
(x/5)-2(2x/5+1)-(28)=0
We add all the numbers together, and all the variables
(+x/5)-2(2x/5+1)-28=0
We multiply parentheses
(+x/5)-4x-2-28=0
We get rid of parentheses
x/5-4x-2-28=0
We multiply all the terms by the denominator
x-4x*5-2*5-28*5=0
We add all the numbers together, and all the variables
x-4x*5-150=0
Wy multiply elements
x-20x-150=0
We add all the numbers together, and all the variables
-19x-150=0
We move all terms containing x to the left, all other terms to the right
-19x=150
x=150/-19
x=-7+17/19
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