(x/5)-4=1+(5/8)

Solution for (x/5)-4=1+(5/8) equation:

(x/5)-4=1+(5/8)

We move all terms to the left:

(x/5)-4-(1+(5/8))=0

We add all the numbers together, and all the variables

(+x/5)-4-(1+(+5/8))=0

We get rid of parentheses

x/5-4-(1+(+5/8))=0

We calculate fractions


8x^2/()-4+()/()=0

We add all the numbers together, and all the variables

8x^2/()-3=0

We multiply all the terms by the denominator


8x^2-3*()=0

We add all the numbers together, and all the variables

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$