(x/5)=4+(x-6)/3

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Solution for (x/5)=4+(x-6)/3 equation: 



(x/5)=4+(x-6)/3

We move all terms to the left:

(x/5)-(4+(x-6)/3)=0

We add all the numbers together, and all the variables

(+x/5)-(4+(x-6)/3)=0

We get rid of parentheses

x/5-(4+(x-6)/3)=0

We calculate fractions


3x^2/()+(-(4+(x-6)*5)/()=0



We calculate terms in parentheses: +(-(4+(x-6)*5)/(), so:

-(4+(x-6)*5)/(

We multiply all the terms by the denominator


-(4+(x-6)*5)



We calculate terms in parentheses: -(4+(x-6)*5), so:

4+(x-6)*5

determiningTheFunctionDomain
(x-6)*5+4

We multiply parentheses

5x-30+4

We add all the numbers together, and all the variables

5x-26

Back to the equation:

-(5x-26)



We get rid of parentheses

-5x+26

Back to the equation:

+(-5x+26)



We get rid of parentheses

3x^2/()-5x+26=0

We multiply all the terms by the denominator


3x^2-5x*()+26*()=0

We add all the numbers together, and all the variables

3x^2-5x*()=0

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