(x/6)+(2x/8)+(3x/10)=2(x-1)

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Solution for (x/6)+(2x/8)+(3x/10)=2(x-1) equation:


x in (-oo:+oo)

x/6+(2*x)/8+(3*x)/10 = 2*(x-1) // - 2*(x-1)

x/6-(2*(x-1))+(2*x)/8+(3*x)/10 = 0

x/6-2*(x-1)+(2*x)/8+(3*x)/10 = 0

x/6-2*(x-1)+x/4+(3*x)/10 = 0

(-2*4*6*10*(x-1))/(4*6*10)+(4*10*x)/(4*6*10)+(6*10*x)/(4*6*10)+(3*4*6*x)/(4*6*10) = 0

4*10*x-2*4*6*10*(x-1)+6*10*x+3*4*6*x = 0

60*x-440*x+72*x+480 = 0

72*x-380*x+480 = 0

480-308*x = 0

(480-308*x)/(4*6*10) = 0

(480-308*x)/(4*6*10) = 0 // * 4*6*10

480-308*x = 0

480-308*x = 0 // - 480

-308*x = -480 // : -308

x = -480/(-308)

x = 120/77

x = 120/77

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