(x/6)+(4/x-4)-(x/x-4)=0

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Solution for (x/6)+(4/x-4)-(x/x-4)=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/6+4/x-(x/x)-4+4 = 0

x/6+4/x-4-1+4 = 0

1/6*x^1+4*x^-1-1*x^0 = 0

(1/6*x^2-1*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(1/6*x^2-1*x^1+4*x^0) = 0

x^1

(1/6)*x^2-x+4 = 0

(1/6)*x^2-x+4 = 0

DELTA = (-1)^2-(4*4*(1/6))

DELTA = -5/3

DELTA < 0

x in { } 

x belongs to the empty set

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