(x/6)+(x+4/2)=(2/x+5

Solution for (x/6)+(x+4/2)=(2/x+5 equation:

(x/6)+(x+4/2)=(2/x+5

We move all terms to the left:

(x/6)+(x+4/2)-((2/x+5)=0


Domain of the equation: x+5)!=0

x∈R


We add all the numbers together, and all the variables

(+x/6)+(x+2)-((2/x+5)=0

We get rid of parentheses

x/6+x-((2/x+5)+2=0

We calculate fractions


x^2/6x+x+()/6x=0

We multiply all the terms by the denominator


x^2+x*6x+()=0

We add all the numbers together, and all the variables

x^2+x*6x=0

Wy multiply elements

x^2+6x^2=0

We add all the numbers together, and all the variables

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$