(x/6)+(x/3)=(3/4)

Solution for (x/6)+(x/3)=(3/4) equation:

(x/6)+(x/3)=(3/4)

We move all terms to the left:

(x/6)+(x/3)-((3/4))=0

We add all the numbers together, and all the variables

(+x/6)+(+x/3)-((+3/4))=0

We get rid of parentheses

x/6+x/3-((+3/4))=0

We calculate fractions


48x^2/()+96x^2/()+()/()=0

We add all the numbers together, and all the variables

48x^2/()+96x^2/()+1=0

We multiply all the terms by the denominator


48x^2+96x^2+1*()=0

We add all the numbers together, and all the variables

144x^2=0

a = 144; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·144·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{288}=0$