(x/6)+(x/5)=(11/30)

Solution for (x/6)+(x/5)=(11/30) equation:

(x/6)+(x/5)=(11/30)

We move all terms to the left:

(x/6)+(x/5)-((11/30))=0

We add all the numbers together, and all the variables

(+x/6)+(+x/5)-((+11/30))=0

We get rid of parentheses

x/6+x/5-((+11/30))=0

We calculate fractions


450x^2/()+540x^2/()+()/()=0

We add all the numbers together, and all the variables

450x^2/()+540x^2/()+1=0

We multiply all the terms by the denominator


450x^2+540x^2+1*()=0

We add all the numbers together, and all the variables

990x^2=0

a = 990; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·990·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{1980}=0$