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(x/6)-2=(10-(1/3)x)
We move all terms to the left:
(x/6)-2-((10-(1/3)x))=0
Domain of the equation: 3)x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+x/6)-((10-(+1/3)x))-2=0
We get rid of parentheses
x/6-((10-(+1/3)x))-2=0
We calculate fractions
3x^2/18x+()/18x-2=0
We multiply all the terms by the denominator
3x^2-2*18x+()=0
We add all the numbers together, and all the variables
3x^2-2*18x=0
Wy multiply elements
3x^2-36x=0
a = 3; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·3·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*3}=\frac{72}{6} =12 $
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