(x/6)-3=2+x

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Solution for (x/6)-3=2+x equation:



(x/6)-3=2+x
We move all terms to the left:
(x/6)-3-(2+x)=0
We add all the numbers together, and all the variables
(+x/6)-(x+2)-3=0
We get rid of parentheses
x/6-x-2-3=0
We multiply all the terms by the denominator
x-x*6-2*6-3*6=0
We add all the numbers together, and all the variables
x-x*6-30=0
Wy multiply elements
x-6x-30=0
We add all the numbers together, and all the variables
-5x-30=0
We move all terms containing x to the left, all other terms to the right
-5x=30
x=30/-5
x=-6

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