(x/6)-4=(11/12)

Solution for (x/6)-4=(11/12) equation:

(x/6)-4=(11/12)

We move all terms to the left:

(x/6)-4-((11/12))=0

We add all the numbers together, and all the variables

(+x/6)-4-((+11/12))=0

We get rid of parentheses

x/6-4-((+11/12))=0

We calculate fractions


12x^2/()-4+()/()=0

We add all the numbers together, and all the variables

12x^2/()-3=0

We multiply all the terms by the denominator


12x^2-3*()=0

We add all the numbers together, and all the variables

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$