(x/8)+(2/x)

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Solution for (x/8)+(2/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/8+2/x = 0

1/8*x^1+2*x^-1 = 0

(1/8*x^2+2*x^0)/(x^1) = 0 // * x^2

x^1*(1/8*x^2+2*x^0) = 0

x^1

(1/8)*x^2+2 = 0

(1/8)*x^2+2 = 0

DELTA = 0^2-(2*4*(1/8))

DELTA = -1

DELTA < 0

x in { } 

x belongs to the empty set

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