(x/8)+(x/7)=(7/16)

Solution for (x/8)+(x/7)=(7/16) equation:

(x/8)+(x/7)=(7/16)

We move all terms to the left:

(x/8)+(x/7)-((7/16))=0

We add all the numbers together, and all the variables

(+x/8)+(+x/7)-((+7/16))=0

We get rid of parentheses

x/8+x/7-((+7/16))=0

We calculate fractions


112x^2/()+128x^2/()+()/()=0

We add all the numbers together, and all the variables

112x^2/()+128x^2/()+1=0

We multiply all the terms by the denominator


112x^2+128x^2+1*()=0

We add all the numbers together, and all the variables

240x^2=0

a = 240; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·240·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{480}=0$