(x/x+2)+(4/x+x)=1

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Solution for (x/x+2)+(4/x+x)=1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+4/x+x/x+2 = 1 // - 1

x+4/x+x/x-1+2 = 0

1*x^1+4*x^-1+2*x^0 = 0

(1*x^2+2*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+2*x^1+4*x^0) = 0

x^1

x^2+2*x+4 = 0

x^2+2*x+4 = 0

DELTA = 2^2-(1*4*4)

DELTA = -12

DELTA < 0

x in { } 

x belongs to the empty set

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