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(x2+1)/3+2=x
We move all terms to the left:
(x2+1)/3+2-(x)=0
We add all the numbers together, and all the variables
(+x^2+1)/3-x+2=0
We add all the numbers together, and all the variables
(+x^2+1)/3-1x+2=0
We multiply all the terms by the denominator
(+x^2+1)-1x*3+2*3=0
We add all the numbers together, and all the variables
(+x^2+1)-1x*3+6=0
Wy multiply elements
(+x^2+1)-3x+6=0
We get rid of parentheses
x^2-3x+1+6=0
We add all the numbers together, and all the variables
x^2-3x+7=0
a = 1; b = -3; c = +7;
Δ = b2-4ac
Δ = -32-4·1·7
Δ = -19
Delta is less than zero, so there is no solution for the equation
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