(x2+2)=(1-x)

Solution for (x2+2)=(1-x) equation:

(x2+2)=(1-x)

We move all terms to the left:

(x2+2)-((1-x))=0

We add all the numbers together, and all the variables

(+x^2+2)-((-1x+1))=0

We get rid of parentheses

x^2-((-1x+1))+2=0


We calculate terms in parentheses: -((-1x+1)), so:

(-1x+1)

We get rid of parentheses

-1x+1

Back to the equation:

-(-1x+1)


We get rid of parentheses

x^2+1x-1+2=0

We add all the numbers together, and all the variables

x^2+x+1=0

a = 1; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·1·1
Δ = -3
Delta is less than zero, so there is no solution for the equation