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(x2+3x+-5)+(-3x^2+-8x+9)=0
We add all the numbers together, and all the variables
(-3x^2+-8x+9)+(+x^2+3x+-5)=0
We use the square of the difference formula
(-3x^2-8x+9)+(+x^2+3x-5)=0
We get rid of parentheses
-3x^2+x^2-8x+3x+9-5=0
We add all the numbers together, and all the variables
-2x^2-5x+4=0
a = -2; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·(-2)·4
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{57}}{2*-2}=\frac{5-\sqrt{57}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{57}}{2*-2}=\frac{5+\sqrt{57}}{-4} $
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