(x2+x+126)=0

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Solution for (x2+x+126)=0 equation: 



(x2+x+126)=0

We add all the numbers together, and all the variables

(+x^2+x+126)=0

We get rid of parentheses

x^2+x+126=0

a = 1; b = 1; c = +126;
Δ = b2-4ac
Δ = 12-4·1·126
Δ = -503
Delta is less than zero, so there is no solution for the equation

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