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(x2-17x+52)=0
We add all the numbers together, and all the variables
(+x^2-17x+52)=0
We get rid of parentheses
x^2-17x+52=0
a = 1; b = -17; c = +52;
Δ = b2-4ac
Δ = -172-4·1·52
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-9}{2*1}=\frac{8}{2} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+9}{2*1}=\frac{26}{2} =13 $
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